Cevap :
[tex] \frac{2y - 1}{5} + \frac{3y + 1}{2} = 4 \\ \frac{2y - 1}{5} + \frac{3y + 1}{2} = \frac{4}{1} \\ \frac{4y - 2}{10} + \frac{15y + 5}{10} = \frac{40}{10} \\ 4y -2 + 15y + 5 = 40 \\ 19y + 3 = 40 \\ 19y = 37 [/tex]
- [tex]y = \frac{37}{19} [/tex]
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